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Unformatted text preview: y > 0, we have x = 2 y > 0 and, therefore, x ( t ) increases. In the lower halfplane, x < 0 and so x ( t ) decreases. This implies that solutions ow from the left to the right in the upper halfplane and from the right to the left in the lower halfplane. See Figure B.30 in the text. 13. First, we will nd the critical points of this system. Therefore, we solve the system ( y x )( y 1) = 0 , ( x y )( x 1) = 0 . 296...
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 Spring '10
 Hald,OH
 Math, Differential Equations, Linear Algebra, Algebra, Equations

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