Unformatted text preview: y > 0, we have x = 2 y > 0 and, therefore, x ( t ) increases. In the lower halfplane, x < 0 and so x ( t ) decreases. This implies that solutions ﬂow from the left to the right in the upper halfplane and from the right to the left in the lower halfplane. See Figure B.30 in the text. 13. First, we will ±nd the critical points of this system. Therefore, we solve the system ( y − x )( y − 1) = 0 , ( x − y )( x − 1) = 0 . 296...
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This note was uploaded on 03/29/2010 for the course MATH 54257 taught by Professor Hald,oh during the Spring '10 term at Berkeley.
 Spring '10
 Hald,OH
 Math, Differential Equations, Linear Algebra, Algebra, Equations

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