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Unformatted text preview: = 0, = 1 / 3, and b = 0 . 22. Since tan = 2 1 b = 4 . 040404 , we take = tan 1 ( 4 . 040404) = 1 . 328172 and get x n = x (2 n ) = e . 22 n sin(0 . 629321 n ) (1 . 092050) sin(1 . 328172) , v n = x (2 n ) = . 11 e . 22 n sin(0 . 629321 n ) + (1 . 258642) e . 22 n cos(0 . 629321 n ) +(1 . 092050) cos(1 . 328172) . 326...
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This note was uploaded on 03/29/2010 for the course MATH 54257 taught by Professor Hald,oh during the Spring '10 term at University of California, Berkeley.
 Spring '10
 Hald,OH
 Math, Differential Equations, Linear Algebra, Algebra, Equations

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