Chapter 6
W
2
(
x
) = (
−
1)
3
−
2
x
x
−
1
1
−
x
−
2
= 2
x
−
1
,
W
3
(
x
) = (
−
1)
3
−
3
x
x
5
1
5
x
4
= 4
x
5
.
Now we divide both sides of the given equation by
x
3
to obtain an equation in standard form,
that is,
y
−
2
x
−
1
y
−
5
x
−
2
y
+ 5
x
−
3
y
=
x
−
5
.
Hence, the righthand side,
g
(
x
), in formula (1) on page 339 of the text equals to
x
−
5
. Applying
formula (11), page 340 of the text, yields
v
1
(
x
) =
x
−
5
(
−
6
x
3
)
48
x
2
dx
=
−
1
8
x
−
4
dx
=
1
24
x
−
3
,
v
2
(
x
) =
x
−
5
(2
x
−
1
)
48
x
2
dx
=
1
24
x
−
8
dx
=
−
1
168
x
−
7
,
v
3
(
x
) =
x
−
5
(4
x
5
)
48
x
2
dx
=
1
12
x
−
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 Spring '10
 Hald,OH
 Math, Differential Equations, Linear Algebra, Algebra, Equations, dx

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