Chapter4Q06answer1[1] - (none of the machines out of...

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Chapter 4 Question 6 a) p (all three machines out of action) = p (machine A out of action) × p (machine B out of action) × p (machine C out of action) = 0.10 × 0.05 × 0.20 = 0.001 b) p
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Unformatted text preview: (none of the machines out of action) p (machine A not out of action) × p (machine B not out of action) × p (machine C not out of action) = 0.90 × 0.95 × 0.80 = 0.684...
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This note was uploaded on 03/29/2010 for the course DMVS 324 taught by Professor Muller during the Spring '10 term at Stellenbosch University-South Africa.

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