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Unformatted text preview: = 0.83 v) 40 cars have faulty brakes. Of these cars, 25 have faulty tires, so p (car has faulty tires given that it has faulty brakes) = 25/40 = 0.63 b) Since the probability of faulty tires increases if a car has faulty brakes – from 0.40 to 0.63 – it appears that the two events are dependent. However, we can only draw this conclusion tentatively as our evidence is based on a sample of only 100 cars....
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- Spring '10