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Unformatted text preview: pi bond. That typically leads you to sp 2 hybridization. For a triple bond youll need a sigma and two pi bonds, so youll need two leftover p orbitals on each atom involved in order to generate two pi bonds. That typically leads you to sp hybridization. Now youre ready to try these: 1. Give the hybridization for the C and the O in H 2 CO (formaldehyde). 2. Give the hybridization for the C and the N in HCN. 3. Give the hybridization for all three atoms in N 2 O. 4. Give the hybridization for the central atom in each of the following: a) BCl 3 b) BrF 3 c) XeF 4 d) TeF 4 5. Using these examples can you describe how the hybrid orbital model combined with Valence Bond Theory helps to explain the bonding, molecular geometries, etc. in these molecules? KEY: 1. sp 2 for both 2. sp for both 3. outer N and the O are sp 2 , inner N is sp 4. a) sp 2 b) sp 3 d c) sp 3 d 2 d) sp 3 d...
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- Spring '06