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Unformatted text preview: pi bond. That typically leads you to sp 2 hybridization. For a triple bond you’ll need a sigma and two pi bonds, so you’ll need two leftover “p” orbitals on each atom involved in order to generate two pi bonds. That typically leads you to sp hybridization. Now you’re ready to try these: 1. Give the hybridization for the C and the O in H 2 CO (formaldehyde). 2. Give the hybridization for the C and the N in HCN. 3. Give the hybridization for all three atoms in N 2 O. 4. Give the hybridization for the central atom in each of the following: a) BCl 3 b) BrF 3 c) XeF 4 d) TeF 4 5. Using these examples can you describe how the hybrid orbital model combined with Valence Bond Theory helps to explain the bonding, molecular geometries, etc. in these molecules? KEY: 1. sp 2 for both 2. sp for both 3. outer N and the O are sp 2 , inner N is sp 4. a) sp 2 b) sp 3 d c) sp 3 d 2 d) sp 3 d...
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- Spring '06
- #, Chemical bond, Phosphorus, Acetylene, Hybridization sp sp2