{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

F09_230_L06_pre[1]

# F09_230_L06_pre[1] - CHEM 230 F09 Lecture 6 Chapter 6...

This preview shows pages 1–12. Sign up to view the full content.

Click to edit Master subtitle style CHEM 230 F09 Lecture 6 Chapter 6: Thermodynamics First Law Session ID: 230

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Wrapping up CH 4 Real Gases Assumptions for an ideal gas Real gases differ from a ideal gases van der Waals coefficients
van der Waals Equation b Correct for assumption that gas particles have no volume a Correct for assumption that gas particles do not attract of repel one another ( 29 nRT = nb V V n a + P nRT = PV - 2

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Correction 1: Volume…b There is a minimum volume for a gas: Vmin min min V = V = T V + P nRT = V then 0, if Vmin depends on n the number of moles b "molar volume" (L mol-1) The volume occupied by a mol of gas particles. nb V nRT = P P nRT = nb V nb + P nRT = V - -
Correction 2: Attractive Forces…a Attractive forces between particles reduce pressure Particles that tend to associate with each other also collide with the container walls less often van der Waals forces (all particles) Polar molecules (HCl) Hydrogen bonding (H2O or NH3)

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Compression Factor For ideal gases, Z = 1 For Z < 1, Vm is less than expected (compressed) Obj1 2
Correction 2: Attractive a a measure of force (J m3 mol-2 or L2 atm mol-2) n the number of moles V container volume Square arises because force requires 2 interacting particles This correction is strictly attractive and does not go far enough to account for full charges 2 attraction attraction - V n a = V nRT = P

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
van der Waals Equation ( 29 nRT = nb V V n a + P nRT = PV - 2
Concept Question Which noble gas will deviate most from ideal behavior? A. He B. Ne C. Ar D. Kr E. Xe F. Rn

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Concept Question Which element or compound will deviate most from ideal gas behavior? A. He B. He1+ C. H2O D. Benzene
Gas A and Gas B are thoroughly mixed 1 g:1 g in a container and reach thermodynamic equilibrium. Gas B has twice the molar mass of Gas A. Which of the following is true? A. Gas B has a greater partial pressure than Gas A

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### Page1 / 37

F09_230_L06_pre[1] - CHEM 230 F09 Lecture 6 Chapter 6...

This preview shows document pages 1 - 12. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online