Problem Set 4_Sol

Problem Set 4_Sol - Answer Key Side 1 of 6 Problem One 2D...

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Answer Key Ch 1a, Problem Set Four Side 1 of 6 1 10 Points -1 for each one wrong up to 10 Problem One – 2D and 3D Nodes – 30 Points a. (10 Pts) For orbitals with quantum numbers n and l , there are l angular nodes and n " l + 1 ( ) radial nodes, giving a total of n " 1 nodes (or we could say n = # total nodes + 1 )… A. number of angular nodes 0, l =0 , so it’s an s orbital, n = # total nodes + 1 =0+1=1 Final Answer: 1s B. number of angular nodes 1 l =1 so it’s a p orbital n = # total nodes + 1 =1+1=2 Final Answer: 2p C. number of angular nodes 2 l =2 so it’s a d orbital n = # total nodes + 1 =2+1=3 Final Answer: 3d D. number of angular nodes 0 l =0 so it’s an s orbital n = # total nodes + 1 =1+1=2 Final Answer: 2s E. number of angular nodes 3 l =3 so it’s a f orbital n = # total nodes + 1 =3+1=4 Final Answer: 4f F. number of angular nodes 1 l =1 so it’s a p orbital n = # total nodes + 1 =2+1=3 Final Answer: 3p G. number of angular nodes 4 l =4 so it’s a g orbital n = # total nodes + 1 =4+1=5 Final Answer: 5g H. number of angular nodes 2 l =2 so it’s a d orbital n = # total nodes + 1 =3+1=4 Final Answer: 4d I. number of angular nodes 0 l =0 so it’s an s orbital n = # total nodes + 1 =2+1=3 Final Answer: 3s J. number of angular nodes 5 l =5 so it’s an h orbital n = # total nodes + 1 =5+1=6 Final Answer: 6h K. number of angular nodes 3 l =3 so it’s an f orbital n = # total nodes + 1 =4+1=5 Final Answer: 5f L. number of angular nodes 6 l =6 so it’s an i orbital n = # total nodes + 1 =6+1=7 Final Answer: 7i
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Answer Key Ch 1a, Problem Set Four Side 2 of 6 2 10 Points order of energies must be arranged as shown. –1 for each one out of order 3 Points 3 Points Problem One – Continued b. (8 Pts) As reconstructed from Gray, the chart is incorrect if one simply puts in the appropriate pictures for 1s, 2s, 2p, etc. By construction of the problem, the energy levels of these surfaces goes by A, B, C, D… therefore the pictures must be moved vertically on
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This note was uploaded on 03/30/2010 for the course CH 1a taught by Professor Lewis during the Fall '08 term at Caltech.

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Problem Set 4_Sol - Answer Key Side 1 of 6 Problem One 2D...

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