Unformatted text preview: De Broglie Wavelength: lamda = h/p; p=mv; 5 points mass = 2*(1.67262158e27 kg + 1.6749286e27 kg) = 3.4e27 kg velocity = 6.3e6 m/s lamda = 1.6e14 m = 16 fm; 5 points 2c ANSWER: resolution = lamda/2 = 7.9 fm. (5 points) nuclear diameter > resolution = 7.9 fm (10 points) 2.4 fm * m^(1/3) > 7.9 fm m > 35.1 (5 points) Chlorine is the smallest nucleus observable with this "microscope" (5 points) Give 20 points partial credit for the "factor of 2 answers", namely lithium (m > 4.4) and "all are observable" (m > 280) 5 points off for sig figs....
View
Full Document
 Fall '08
 Lewis
 Uncertainty Principle, Adrenergic receptor, Matter wave

Click to edit the document details