HW_09_S

HW_09_S - Ph1a Solutions 9 Chefung Chan (cchan@caltech.edu)...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Ph1a Solutions 9 Chefung Chan (cchan@caltech.edu) 27 November 2004 Each homework problem is worth 5 points. Please disregard the point values listed on the problem itself. Use these instead. 9.1 FP4 (5 points) 9.1.a (1 point) The total energy E is given by: E = K + U = 1 2 mv 2- GMm r = 1 2 m parenleftbigg GM 5 R parenrightbigg- GMm 5 R E =- GMm 10 R Because E < 0, the orbit will be elliptical. 9.1.b (1 point) The magnitude of the angular momentum vector L is | vector L | = | vector r vector p | = (5 R )( mv ) sin 135 | vector L | = m radicalBig 5 2 GMR 9.1.c (1.5 points) The equations for conservation of energy and angular momentum are respectively: E =- GMm 10 R = 1 2 mv 2 p- GMm r p | vector L | = m radicalBig 5 2 GMR = mv p r p Solving the second equation for r p gives r p = radicalBig 5 2 GMR/v 2 p Substituting into the energy equation:- GMm 10 R = 1 2 mv 2 p- GMm v p radicalBig 5 2 GMR v 2 p- 2 parenleftBigg radicalbigg 2 GM 5 R parenrightBigg v p + GM 5 R = 0...
View Full Document

This note was uploaded on 03/30/2010 for the course PH 1a taught by Professor Goodstein during the Fall '07 term at Caltech.

Page1 / 4

HW_09_S - Ph1a Solutions 9 Chefung Chan (cchan@caltech.edu)...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online