{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

PHY303L Homework%206 - homework 06 FAUSAK TAYLOR Due 4:00...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
homework 06 – FAUSAK, TAYLOR – Due: Feb 25 2008, 4:00 am 1 Question 1, chap 28, sect 4. part 1 of 2 10 points A 28 V battery has an internal resistance r . 1 A 28 V r 42 Ω 56 Ω internal resistance What is the value of r ? Answer in units of Ω. Question 2, chap 28, sect 4. part 2 of 2 10 points Determine the magnitude of the current through the 56 Ω resistor on the right-hand side of the circuit. Answer in units of A. Question 3, chap 28, sect 4. part 1 of 3 10 points 7 . 2 V 1 V 4 . 7 V I 1 1 . 3 Ω 2 Ω I 2 7 . 7 Ω I 3 9 . 7 Ω Find the current I 1 in the 1 . 3 Ω resistor at the bottom of the circuit between the two power supplies. Answer in units of A. Question 4, chap 28, sect 4. part 2 of 3 10 points Determine I 2 . Answer in units of A. Question 5, chap 28, sect 4. part 3 of 3 10 points Determine I 3 . Answer in units of A. Question 6, chap 28, sect 4. part 1 of 3 10 points In the circuit below R 1 = R 2 = R , R 3 = 2 R , and R 4 = 4 R . E C D A B i 1 R 1 i 2 R 2 i 3 R 3 i 4 R 4 I 5 Find R AB when R = 1 . 6 Ω . Answer in units of Ω. Question 7, chap 28, sect 4. part 2 of 3 10 points Find the ratio i 3 i 4 . 1. i 3 i 4 = 1 4 2. i 3 i 4 = 1 3 3. i 3 i 4 = 0 4. i 3 i 4 = 1 2 5. i 3 i 4 = 1 6. i 3 i 4 = 3 7. i 3 i 4 = 8 8. i 3 i 4 = 4 9. i 3 i 4 = 1 8 10. i 3 i 4 = 2
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
homework 06 – FAUSAK, TAYLOR – Due: Feb 25 2008, 4:00 am 2 Question 8, chap 28, sect 4. part 3 of 3 10 points Let I = 7 . 6 A. Find i 5 . Answer in units of A. Question 9, chap 28, sect 4. part 1 of 4 10 points Twelve resistors, each of equal value R = 2 . 4 Ω, are connected so that each is along one edge of a cube, as shown in the figure. A current of I = 7 . 5 A is introduced at point “a”. The current will be allowed to exit only along a wire at point “b”, as drawn. a d e h g b c f 6 12 10 7 3 5 8 1 2 4 11 9 I I What is the current through resistor R 2 ? Answer in units of A. Question 10, chap 28, sect 4. part 2 of 4 10 points What is the current through resistor R 7 ? Answer in units of A. Question 11, chap 28, sect 4. part 3 of 4 10 points What is current through resistor R 10 ? Answer in units of A.
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}