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Unformatted text preview: homework 06 FAUSAK, TAYLOR Due: Feb 25 2008, 4:00 am 1 Question 1, chap 28, sect 4. part 1 of 2 10 points A 28 V battery has an internal resistance r . 1 A 28 V r 42 56 internal resistance What is the value of r ? Answer in units of . Question 2, chap 28, sect 4. part 2 of 2 10 points Determine the magnitude of the current through the 56 resistor on the righthand side of the circuit. Answer in units of A. Question 3, chap 28, sect 4. part 1 of 3 10 points 7 . 2 V 1 V 4 . 7 V I 1 1 . 3 2 I 2 7 . 7 I 3 9 . 7 Find the current I 1 in the 1 . 3 resistor at the bottom of the circuit between the two power supplies. Answer in units of A. Question 4, chap 28, sect 4. part 2 of 3 10 points Determine I 2 . Answer in units of A. Question 5, chap 28, sect 4. part 3 of 3 10 points Determine I 3 . Answer in units of A. Question 6, chap 28, sect 4. part 1 of 3 10 points In the circuit below R 1 = R 2 = R , R 3 = 2 R , and R 4 = 4 R . E C D A B i 1 R 1 i 2 R 2 i 3 R 3 i 4 R 4 I 5 Find R AB when R = 1 . 6 . Answer in units of . Question 7, chap 28, sect 4. part 2 of 3 10 points Find the ratio i 3 i 4 . 1. i 3 i 4 = 1 4 2. i 3 i 4 = 1 3 3. i 3 i 4 = 0 4. i 3 i 4 = 1 2 5. i 3 i 4 = 1 6. i 3 i 4 = 3 7. i 3 i 4 = 8 8. i 3 i 4 = 4 9. i 3 i 4 = 1 8 10. i 3 i 4 = 2 homework 06 FAUSAK, TAYLOR Due: Feb 25 2008, 4:00 am 2 Question 8, chap 28, sect 4. part 3 of 3 10 points Let I = 7 . 6 A. Find i 5 . Answer in units of A. Question 9, chap 28, sect 4. part 1 of 4 10 points Twelve resistors, each of equal value R = 2 . 4 , are connected so that each is along one edge of a cube, as shown in the figure. A current of I = 7 . 5 A is introduced at point a. The current will be allowed to exit only along a wire at point b, as drawn. a d e h g b c f 6 12 10 7 3 5 8 1 2 4 11 9 I I What is the current through resistor R 2 ? Answer in units of A. Question 10, chap 28, sect 4. part 2 of 4 10 points What is the current through resistor R 7 ?...
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 Spring '07
 KBrowning

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