9.11-9.12

9.11-9.12 - Equilibrium Equilibrium OH + CH3I 1- CH3OH + I...

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1 OH 1- + CH 3 I CH 3 + I 1- So wait as sec, if we start with reactants, initial R f > initial R r What happens as reactants go down in concentration, and products build up ? R f slows R r speeds up Until…… R f = R r …..at Equilibrium Section 9.11 Equilibrium Equilibrium is defined as when: rate of the forward reaction = rate of the reverse reaction G = 0 CH 3 I + OH 1- I 1- + CH 3 OH R f = k f [OH 1- ] [CH 3 I] R r = k r [I 1- ] [CH 3 OH] At equilibrium: R f = R r k f [OH 1- ] [CH 3 I] k r [I 1- ] [CH 3 OH] = [I 1- ] [CH 3 OH] = k f k r [OH 1- ] [CH 3 I] = Products Reactants = K Equilibrium constant Section 9.11 Equilibrium Time Tokens of S1 Tokens of S2 0 24 0 1 2 3 4 5 Section 9.11 Understanding Keq Student 1 24 tokens Student 2 0 tokens Gives 1/3 tokens Gives 1/5 tokens k forward = 0.33 tokens/min k reverse = 0.20 tokens/min S1 S2 Only work with whole numbers, discard fractions, do not round up. 24-8 +0 = 16 0 +8 = 8 16-5 +1 = 12 8-1 +5 = 12 12-2 +4 = 14 12-4 +2 = 10 10-3 +2 = 9 14-2 +3 = 15 15-3 +3 = 15 9-3 +3 = 9 E Reaction Coordinate Time Tokens of S1 Tokens of S2 0 24 0 1 2 3 4 5 Section 9.11 Understanding Keq 24-8 +0 = 16 0 +8 = 8 16-5 +1 = 12 8-1 +5 = 12 12-2 +4 = 14 12-4 +2 = 10 10-3 +2 = 9 14-2 +3 = 15 15-3 +3 = 15 9-3 +3 = 9 Rate forward got slower Rate reverse got faster Mother Nature will always settle in at the lowest energy. She settled in with S1 had 9 tokens, and S2 had 15 tokens Section 9.11 Understanding Keq Student 1 0 tokens Student 2 24 tokens Gives 1/3 tokens Gives 1/5 tokens k forward = 0.33 tokens/min k reverse = 0.20 tokens/min S1 S2 Only work with whole numbers, discard fractions, do not round up. E Reaction Coordinate Time Tokens of S1 Tokens of S2 0 0 24 1 2 3 4 5 0 +4 = 4 24-4 +0 = 20 4-1 +4 = 7 20-4 +1 = 17 17-3 +2 = 16 7-2 +3 = 8 8-2 +3 = 9 16-3 +2 = 15 15-3 +3 = 15 9-3 +3 = 9 Section 9.11 Understanding Keq Time Tokens of S1 Tokens of S2 0 0 24 1 2 3 4 5 0 +4 = 4 24-4 +0 = 20 4-1 +4
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9.11-9.12 - Equilibrium Equilibrium OH + CH3I 1- CH3OH + I...

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