10_Midterm_Solution

10_Midterm_Solution - EE 101A MIDTERM WINTER 10 NAME I.D....

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- 1 - EE 101A MIDTERM WINTER 10 NAME ________SOLUTION ___________ I.D. NUMBER ______________________________ SIGNATURE ______________________________ TIME : 90 MINUTES OPEN BOOKS, OPEN NOTES NO PC or WIRELESS COMMUNICATION DEVICES STATE YOUR ASSUMPTIONS AND REASONING NO CREDIT FOR ANSWERS WITHOUT REASONING (1) __________/50 (2) __________/35 (3) __________/15 Total __________/100
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- 2 - 1) Consider the circuit shown. The I-V characteristic of the non-linear component Y is shown in the following page. (50%) a) Determine the voltage V Y , current I Y and power of the component Y. Is component Y dissipating or supplying power ? + _ 10V 4mA + V Y _ I Y 1K 0.5K Y 2V - + 0.5K Find the Thevenin equivalent circuit for the left portion of the circuit (excluding “Y”). + _ 10V + V OC1 _ 1K 0.5K 0.5K O.C. S.C. V OC1 = 10V [1K / (1K +0.5K +0.5K )] = 5V 4mA 1K 0.5K 0.5K + V OC2 _ S.C. S.C. Convert the 4mA and 0.5K into Thevenin equivalent circuit 1K 0.5K 0.5K + V OC2 _ S.C. S.C. 2V - + V OC2 = ( 2V) [1K / (1K +0.5K +0.5K )] = 1V
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- 3 - 1K 0.5K 2V - + 0.5K + V OC3 _ O.C. S.C. V OC3 = (-2V) [(0.5K +0.5K ) / (1K +0.5K +0.5K )] = 1V By superposition, V OC = V OC1 + V OC2 + V OC3 = 5V – 1V – 1V = 3V R T 1K 0.5K 0,5K
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This note was uploaded on 03/30/2010 for the course EE 101A taught by Professor Wong during the Winter '08 term at Stanford.

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10_Midterm_Solution - EE 101A MIDTERM WINTER 10 NAME I.D....

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