Handout_8_Appendix_2

Handout_8_Appendix_2 - Example2 K,' (WL) = 0.25mA/V2 I/t= l...

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Example 2 K,' (WL) = 0.25 mA/V2 I/t= l.5Y ).= 0.02Y'l D c e^rlr,,i e f rri'Io hc i Go C + o,c, kea oVe f<ce@t6 EC. o,e, (ro,c, -? J'* a-" g.s s.{ I Ca o. c. ,'*rv'=9 O+ ({)(Vr-{ ,of( Ap'.*$i:n=o{^.Dc Qsic t3V-Vo W'O Ve'Uo = h#t ros 'D I ottl o lr*t,o t0K , crfs u yr Vg r 4.tV Ver Vc t cq tV t+rQo-r.tj t - ,i." Jolrr, f,3 r l,ln} (t t'2 rgv vg <ve ,, %s . q N ) Vr.lfrl y\t, osFOT c**' ({ ': trv Ios ildtFe tr rh sqhr.fiJ
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O*sis loM
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This note was uploaded on 03/30/2010 for the course EE 101A taught by Professor Wong during the Winter '08 term at Stanford.

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Handout_8_Appendix_2 - Example2 K,' (WL) = 0.25mA/V2 I/t= l...

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