Unformatted text preview: such that the closed loop dominant time constant is around ( τ r =10); (e) Assume the process initially rest at h s = 0.8 m, simulate the closed loop control system performance for ∆h s = 0.2 m at t=0 min (step input of 0.2m from 0.8 m to 1.0 m) ∆h s = 0.5 m at t=100 min (step input of 0.5m from 1.0 m to 1.5 m) ∆h s = − 0.5 m at t=200 min (step input of − 0.5m from 1.5 m to 1.0 m) ∆h s = 0.5 m at t=300 min (step input of − 0.5m from 1.0 m to 0.5 m) ∆h s =0.5 m at t=400 min (step input of 0.5m from 0.5 m back to 1.0 m) Comments on the performance of each design scheme. Note: 1. During the simulation, you may schedule the controllers based on the desired set-point level in part (b) of the model scheduling method. 2. You must use the original non-linear model as the process during the simulation....
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- Spring '10
- direct synthesis method, initial steady-state conditions