process control assignment 3.1

# process control assignment 3.1 - equation 1 dhdt=1pi...

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equation 1: = - - . dhdt 1pi 14h h2Fi 32 h0 5 = - - . - . 1pi Fi4h h2 324h0 5 h1 5 equation 2: - = - - - - ( - )+ - ( - ) Fi 4h h2 Fis4hs hs 2 Fis4hs hs 24 2hs h h s 14hs hs 2 Fi Fis equation 3: . - . = . - . - ( . - . ) - . - . . ( - ) 14h0 5 h1 5 14hs 0 5 hs 1 5 1 4hs 0 5 hs 1 5 22hs 0 5 1 5hs 0 5 h h s equation 4: - = Fi Fis u equation 5: - = h hs y Substituting eqn 2 to eqn 5 into eqn 1: equation6: = . Fis 32hs 0 5 = [ - - - - + - dy dt 1pi Fis4hs hs 2 Fis4hs hs 24 2hs y 14hs hs 2u - . - . + ( . - . ) - . - . . ] 32 14hs 0 5 hs 1 5 321 4hs 0 5 hs 1 5 22hs 0 5 1 5hs 0 5 y = [- - - + - + ( . - . ) - . - 1pi Fis4hs hs 24 2hs y 14hs hs 2u 321 4hs 0 5 hs 1 5 22hs 0 5 . . ] 1 5hs 0 5 y a) Substitute F is = 1.35 m 3 /min, h s = 1.0 m into equation 6: = [ - . + + ] dydt 1pi 2 73 y 13u 336y = [ - + ] 1pi 4960 y 13u

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= + Ys us3πs 4920 = ( )/( + ) 2049u s 6049πs 1 K = 20/49; T = (60/49)*pi; Tr = 10; Kc = T/(K*Tr); = 0.942 Ki = 1/(K*Tr); = 0.245 b) Substitute F is = 1.35 m 3 /min, h s1 = 0.5 m into equation 6: = [ - .
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## This note was uploaded on 03/31/2010 for the course EEE 4265 taught by Professor Ng during the Spring '10 term at Nanyang Technological University.

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process control assignment 3.1 - equation 1 dhdt=1pi...

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