# ch10 - padilla(tp5647 HW10 Gases I shear(52375 This...

This preview shows pages 1–3. Sign up to view the full content.

padilla (tp5647) – HW10: Gases I – shear – (52375) 1 This print-out should have 19 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. You will need to look up conversion factors and values of R in the back of your textbook. 001 (part 1 of 3) 10.0 points Convert 282 . 238 mm Hg into the unit atm. Correct answer: 0 . 371366 atm. Explanation: P = 282 . 238 mm Hg P in atm = ? P = (282 . 238 mm Hg) parenleftbigg 1 atm 760 mm Hg parenrightbigg = 0 . 371366 atm 002 (part 2 of 3) 10.0 points Convert 3 . 59469 atm into the unit Pa. Correct answer: 3 . 64232 × 10 5 Pa. Explanation: P = 3 . 59469 atm P in Pa = ? P = (3 . 59469 atm) parenleftbigg 101.325 kPa atm parenrightbiggparenleftbigg 1000 Pa kPa parenrightbigg = 3 . 64232 × 10 5 Pa 003 (part 3 of 3) 10.0 points Convert 6 . 09335 kPa into the unit torr. Correct answer: 45 . 7039 torr. Explanation: P = 6 . 09335 kPa P in torr = ? P = (6 . 09335 kPa) parenleftbigg 1 atm 101.325 kPa parenrightbigg × parenleftbigg 760 torr atm parenrightbigg = 45 . 7039 torr 004 10.0 points For an ideal gas, pressure has what relation- ship to volume provided only pressure and volume are allowed to change? 1. equal 2. unrelated 3. proportional 4. inversely proportional correct Explanation: Boyle’s law, P = k 1 V or P 1 V , relates the volume and pressure of a sample of gas at constant temperature. This relationship is an inverse proportionality. 005 10.0 points A balloon filled with helium gas has a volume of 603 mL at a pressure of 1 atm. The balloon is released and reaches an altitude of 6.5 km, where the pressure is 0.5 atm. Assuming that the temperature has remained the same, what volume does the gas occupy at this height? Correct answer: 1206 mL. Explanation: P 1 = 1 atm P 2 = 0.5 atm V 1 = 603 mL V 2 = ? Applying Boyle’s law, P 1 V 1 = P 2 V 2 V 2 = P 1 V 1 P 2 = (1 atm) (603 mL) 0.5 atm = 1206 mL 006 10.0 points If the temperature of an ideal gas is raised from 100 C to 200 C, while the pressure re- mains constant, the volume 1. None of these correct 2. goes to 1 2 of the original volume. 3. increases by a factor of 100. 4. remains the same. 5. doubles. Explanation: T 1 = 100 C + 273 = 373 K T 2 = 200 C + 273 = 473 K

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
padilla (tp5647) – HW10: Gases I – shear – (52375) 2 Volume is directly proportional to temper- ature expressed on the Kelvin scale: V 1 T 1 = V 2 T 2 V 2 V 1 = T 2 T 1 The temperature changes by a factor of T 2 T 1 = 473 K
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern