This preview shows pages 1–2. Sign up to view the full content.
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
Unformatted text preview: padilla (tp5647) – HW10: Gases I – shear – (52375) 1 This printout should have 19 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. You will need to look up conversion factors and values of R in the back of your textbook. 001 (part 1 of 3) 10.0 points Convert 282 . 238 mm Hg into the unit atm. Correct answer: 0 . 371366 atm. Explanation: P = 282 . 238 mm Hg P in atm = ? P = (282 . 238 mm Hg) parenleftbigg 1 atm 760 mm Hg parenrightbigg = 0 . 371366 atm 002 (part 2 of 3) 10.0 points Convert 3 . 59469 atm into the unit Pa. Correct answer: 3 . 64232 × 10 5 Pa. Explanation: P = 3 . 59469 atm P in Pa = ? P = (3 . 59469 atm) parenleftbigg 101.325 kPa atm parenrightbiggparenleftbigg 1000 Pa kPa parenrightbigg = 3 . 64232 × 10 5 Pa 003 (part 3 of 3) 10.0 points Convert 6 . 09335 kPa into the unit torr. Correct answer: 45 . 7039 torr. Explanation: P = 6 . 09335 kPa P in torr = ? P = (6 . 09335 kPa) parenleftbigg 1 atm 101.325 kPa parenrightbigg × parenleftbigg 760 torr atm parenrightbigg = 45 . 7039 torr 004 10.0 points For an ideal gas, pressure has what relation ship to volume provided only pressure and volume are allowed to change? 1. equal 2. unrelated 3. proportional 4. inversely proportional correct Explanation: Boyle’s law, P = k 1 V or P ∝ 1 V , relates the volume and pressure of a sample of gas at constant temperature. This relationship is an inverse proportionality. 005 10.0 points A balloon filled with helium gas has a volume of 603 mL at a pressure of 1 atm. The balloon is released and reaches an altitude of 6.5 km, where the pressure is 0.5 atm. Assuming that the temperature has remained the same, what volume does the gas occupy at this height? Correct answer: 1206 mL. Explanation: P 1 = 1 atm P 2 = 0.5 atm V 1 = 603 mL V 2 = ? Applying Boyle’s law, P 1 V 1 = P 2 V 2 V 2 = P 1 V 1 P 2 = (1 atm) (603 mL) 0.5 atm = 1206 mL 006 10.0 points If the temperature of an ideal gas is raised from 100 ◦ C to 200 ◦ C, while the pressure re mains constant, the volume 1. None of these correct 2. goes to 1 2 of the original volume....
View
Full
Document
This note was uploaded on 03/31/2010 for the course CH ch302 taught by Professor F during the Spring '09 term at University of TexasTyler.
 Spring '09
 f

Click to edit the document details