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Unformatted text preview: 1.2N R = 1.5N C Then, N C /N R = 1.2/1.5 = 0.8 Therefore, the largest allowable value for N C is 80% of N R . 1.6-(a) Let cache access time be 1 and main memory access time be 20. Every instruction that is executed must be fetched from the cache, and an additional fetch from the main memory must be performed for 4% of these cache accesses. Therefore, 1 . 11 ) 20 04 . ( ) 1 . 1 ( 20 . 1 = × + × × = factor Speedup...
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- Spring '08
- FROOSH
- Trigraph, access time, time units, Load Load Add, successive program completions
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