problem_set_3

problem_set_3 - Name Student ID number MICROBIOLOGY 140...

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Name Student ID number MICROBIOLOGY 140 Due December 2 nd at the beginning of class Problem Set #3 1. A glucose limited chemostat is operated at a dilution rate of 0.15 hr -1 . If Ks for glucose is 1.8 x10 -7 M, the glucose growth yield constant (Y) is 0.28 and the same medium supports a doubling time of 45 min. in a turbidostat answer the following questions. a) What is the kmax for cells growing in this medium? b) What concentration of glucose would you add to the reservoir to maintain a steady-state cell density in the growth vessel of 400μg/ml c) After resetting the flow rate of the chemostat, you find that the steady-state concentration of glucose is 2.7 x 10 -7 M, at what dilution rate is it now operating? d) What are the two key features of a chemostat operating at steady-state? e) In a 300 ml chemostat, what should be the flow rate in minutes for maintaining a generation time (g) of 4.3 hrs 2. A colleague of yours asks your help in explaining a “strange” result. Using a maltose limited chemostat your
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problem_set_3 - Name Student ID number MICROBIOLOGY 140...

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