pracexam2 - EE-202 Exam II Practice Probs MULTIPLE CHOICE....

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Unformatted text preview: EE-202 Exam II Practice Probs MULTIPLE CHOICE. 1. The frequency domain equivalent of an initialized inductor L is: (7) Something else 2. The step response of a particular circuit with no initial conditions is vout(t)=1!e!t( )u(t). The impulse response is: (1) !(t)(2) u(t) (3) !(t)+e"tu(t)(4) e!tu(t)(5) 1!e!t( )"(t)(6) 1+e!t( )u(t)(7) Something else EE-202, Ex 2, page 2 3. In the circuit below with vC(0!)=5volt, VC(s)at s= 2 is: (1) 4.0 (2) 3.6 (3) 3.2 (4) 2.8 (5) 2.4 (6) 2.0 (7) Something else 4. The transfer function of the circuit below is 1)(+=BsAsHwhere (A, B) is: (Hint: write a node equation at v(t).) (1) (-1, 3) (2) (1, 3) (3) (-1, 2) (4) (1, 2) (5) (-1, 1) (6) (1, 1) (7) Something else 5. In the circuit below with )(1=!cvvoltand 1)(2=!cvvolt, the switch is turned to A-C for 1<!tand 2!tand turned to B-C for 21<!t. Then, )(tvoat t= 2.5 is: (1) 1 (2) 2 (3) 1 (4) 2 (5) 3 (6) 3 (7) Something else EE-202, Ex 2, page 3 6. Let v(t) be the output and vi(t) the input. In order for the circuit below to be stable in the sense of BIBO, the range of mmost be: (1) m!1(2) 1 > m (3) m!(4) 0 > m (5) 1!"m(6) m > -1 (7) Something else 7. The transfer function of a system is given as )1(1)(sssH+=. When )()45cos(22)(tuttvi!+=is applied as the input, the output becomes )()cos()(tutAtvo!+=where ),(!Ais: (1) )135,4(!!(2) )90,4(!!(3) )45,4(!!(4) )45,2(!!(5) )90,2(!!(6) )135,2(!!(7) Something else 8. The impulse response of a system is given as u(t-1). When )()(tuetvti!=is applied to this system as the input, the output )(tvois: (1) )1()1(!!!tuet(2) )1(!!tuet(3) )()1(tuetut!+!(4) )1()1()1(!!!!tuet(5) )1()()1(!!!!tuetut(6) )1()1(!!!tuet(7) Something else EE-202, Ex 2, page 4 9. The following is the magnitude frequency response of a transfer function H(s). The best pole-zero plot leading to this magnitude response is: (5) Something else EE-202, Ex 2, page 5 10. A transfer function, H(s), has one zero, z, and two poles, 1pand 2p, as shown in the figure. Then, )(jH!is: Tangent Table xdeg !.!6.26!.45!3.56!4.63!2.68!6.71!1.74!.76tan(x) 0.0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 (1) !60!(2) !30!(3) !(4) !30(5) !60(6) !90(7) Something else 11. The convolution between )(6tuet!and )(5tuet!is )()(5tuCBeAett++!!where Ais: (1) 1 (2) 2 (3) 3 (4) 0 (5) -2 (6) -1 (7) Something else 12. At t = 0-, all capacitors are relaxed. At t = 0, the switch moves to position A. At t = 1, the switch moves to position B. vout(1+) = (in volts): (1) 12 (2) 2 (3) 3 (4) 4 (5) 8 (6) 6 (7) none of above EE-202, Ex 2, page 6 13. A linear circuit with a transfer function H(s)=Vout(s)Vin(s)=16s+4s2+4s+16has an input vin(t)=2cos(4t)V. The output of the circuit in the steady state has a magnitude and phase (in degrees) equal to: (1) 4, 45o(2) 2, !45o(3) 4, !45o(4) 42, 45o(5) 42, !45o(6) 8, !45o(7) 8, 45o(8) None of above 14. In the circuit below, vC(0-) = 2 V and iL(0-) = 0. The node equation at node A which accounts for all initial conditions is: (1) 2+5s+0.5s!...
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pracexam2 - EE-202 Exam II Practice Probs MULTIPLE CHOICE....

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