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hw9sol

# 81 d1 12 1 w000055 hfreqsndw

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Unformatted text preview: .005:5; >> h=freqs(n,d,w); >> plot(w,abs(h)) >> grid >> xlabel('Frequency r/s') >> ylabel('magnitude response') (c) Normalized frequency: 1.115Hz @ normalized gain (1.875*0.707 1.325625) (i) 600 2 3381.86 1.115 (ii) 1 14.788 10 · 3381.86 20 10 (iii) ·, 14.79 Ω , ·, 14.79 Ω , , , , , · · 20 20 Page 3 / 11 ECE 202 HW solution #9 for prob. 33~36 Prof. DeCarlo (d) Optional *****Netlist for hspice simulation***** .option post node list vin vin 0 1 ac 1 R1 vin vf 14790 R2 vf vp 14790 C1 vf vout 20n C2 vp 0 20n RA vn 0 10000 RB vn vout 10000 E1 vp vn vout 0 100000000K gain) .ac DEC 1024 1 100MEG .print ac v(vout) .end **for an ideal opamp(Exx vin+ vin- vout+ vout- ( freq 526 Hz) Page 4 / 11 ECE 202 HW solution #9 for prob. 33~36 Prof. DeCarlo 34. (a) h(t) = 2u(t − 1) + u(t − 2) − 2u(t − 3) − u(t − 5) 3 2.5 2 h(t) 1.5 1 0.5 0 -6 -4 -2 0 t 2 4 6 (i) f1(t) = δ(t)-1.5δ(t − 1) When a function is convoluted with an impulse function, Kδ(t−T) ∗ f(t) = Kf(t−T) that function will be scaled by the strength of the impulse function and shifted by the amount the impuls...
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