{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

L5-W2L2-160s10matrixproduct

# L5-W2L2-160s10matrixproduct - Matrices matrix product...

This preview shows pages 1–4. Sign up to view the full content.

Matrices matrix product Matrix multiplication A · B is defined only if the number of columns of matrix A is the same as the number of rows of matrix B . A mxp · B pxn = C mxn , p is the number of columns of A and p is the number of rows of B . The resulting matrix C has the same number of rows as A and the same number of columns as B Matrix multiplication is defined in terms of multiplying a row matrix by a column matrix. Both matrices must have the same number of elements. A = 1 2 and , B = 3 4 (1) A · B = 1 2 · 3 4 = 1 · 3 + 2 · 4 = 11 (2)

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
Matrices matrix product C = A · B = 1 2 3 4 · 4 3 2 1 = c 11 c 12 c 21 c 22 = 8 5 20 13 (3) c ij is the element in row i and column j of matrix C = AB c ij is found by multiplying row i of matrix A by column j of matrix B c ij = ith row of A ·

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern