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Unformatted text preview: 10 V 8 k Ω 1 k Ω 1 mV 10 k Ω 1 mA 1 AC Equivalent Circuit Short dc voltage sources Open dc current sources Short capacitors Use for ac analysis (gain A, R in , R out ) RC Vout Vs Rs Rin A=Vout/Vin R2 R1 Vin RL Rout C2 C1 RE VCC C3 1 TModel General model ac resistances ac α and β Simplified model I I b c ac = β I I e c ac = α C rc' Ic E rb' B re' Ib Ie C Ic E B re' Ib Ie 1 AC Emitter Resistance Formula: Link between dc and ac analysis ac β vs. dc β re mV I E ' = 25 1 Activity 2 For the transistor amplifier whose dc characteristics were studied in activity 1 Show the ac equivalent circuit Show the ac equivalent circuit in which the transistor is replaced by the T model Compute r e ’ 10 V 8 k Ω 1 k Ω 1 mV 10 k Ω 1 mA 1 Activity 2  solution 10 V 8 k Ω 1 k Ω 1 mV 10 k Ω 1 mA...
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This note was uploaded on 04/04/2010 for the course BME 302L taught by Professor Maarek during the Spring '08 term at USC.
 Spring '08
 Maarek

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