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1P03 assignment #3

# 1P03 assignment #3 - MCMASTER UNIVERSITY 1P03 Assignment#3...

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MCMASTER UNIVERSITY 1P03 Assignment #3 Design Modeling, Analysis and Optimization Simon Edwards 0949966 11/26/2009

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Question #1 Cost is determined, when based on the strength constraint, by graphing Cost per Unit Volume (\$/ m 3 ) vs. Elastic Limit (MPa), where the lower the K h , the better the material. On this graph, the K h is the utility constant, and is represented by diagonal lines across the graph. Therefore, the optimization of materials can be classified based on which section between the diagonal lines from the bottom right. Because high/low carbon steels are classed lower to the right, with a K h from 0.2- 0.3, it is the best material. The next best material would be aluminum alloys with a K h from 0.3 - 0.7, and then magnesium alloys, with a K h from 0.6 - 1.1. If the cost is being determined based on the deflection constraint, the K h from the Cost per Unit Volume (\$/m 3 ) vs. Young’s Modulus (GPa) graph would be ranked, with again the smaller K h being associated with the best material. High/low carbon steel would be the best material again, with a K h from 0.5 - 1.5, followed by aluminum alloys again, with a K h from 1.0 - 1.5 and lastly followed by magnesium alloys, with a K h from 2.7 - 3.0, deeming them the least optimal material. When weight is determined based on the strength constraint, the Density (Mg/m 3 ) vs. Elastic Limit (MPa) graph is used, with the lower the material index, the more desirable the material. Therefore, based on the K h

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1P03 assignment #3 - MCMASTER UNIVERSITY 1P03 Assignment#3...

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