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Problem set # 1 - Solution

# Problem set # 1 - Solution - AHHﬁHtﬁ 9YM1'HE519 CH4...

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Unformatted text preview: \ AHHﬁHtﬁ 9YM1'HE519 CH4+ “3-D '—':-p C01‘ “.1 R1 {'0 + ”1.0 '7 Cola-H1 R2 R1: awngﬁy 39%;“ Lu 4MW: Ci mm + mm = o Hmum 4r 2pm +2341 =0 Oiluﬂlo+1ym=o WE'LL 50E VCJ-Iq.=-1'-_§? Van =1, Flaw Hut Wig: 419.10; Vﬂzo = "1.153% m... m 0 Wm azuM‘w 4'(**‘)+2(-'¥)+2V»ﬁo =7 V»; :3. 19mm 194 [5 CH4+Hlo -: co 1— 314: R2: 3 WMLW +3315. 9.: 4 “chm ; M1 4- 3H; —-"':’ ,1qu; 'azz my use“, PW Soiution There are three reactions involving it} oompounds. so I = ID and K = 3. The reac- tions are already halaDCe-d. We list the compounds in the ﬁrst oolunut. and write the stoiehitimetrie coefﬁcients for each reaction in the next titres: eolunms: Compound R1 Ill R3 ”:1 ”:2 “r3 NaC] -2 H1504 — I NHESD‘ + 1 _ 1 HCI + 2 {I —2 Nags + 1 — [ C02 +2 Cami}, —1 healer)3 + l as +1 Then we calculate the net generation or consumption by adding up the eoe‘ﬂieiettts across each row {Table 1.1}. Negatitm numbers in the Net column indicate net con— i sumptjon of that. compound; positive numbers indicate. met generation | The Net eoiumn of Table l.l tells us that. for every mole of desired produet 1- [NEECUJI generated, we Dmtsurne. 1 moles ofNaCL 1 male of HQSD‘, 2 moles are. and 1 mole of C3013]. We also generate several waste products: 2 moles of HCI, 1 moles of CG}, and l mole of (235. We can write this information compactly as a. net ehernieai reaction: area + stm + 2c + cameo3 4 2mm + see! + Nazﬂﬂg + 0.15 Generation-Consumption Analysis of the LeBlanc Process Compound R1 R2 ”r2. s3: Mm»; Psalmist: Solution These 5 reactions involve 14 tiiffea'ent mmpmmds. Let‘s us: the gmcmtian— consumpﬂon analysis in Tittle Lls to Must: this set of chemical Muss: :- .. Generation—Consumption Analysis of the Solvay Process {ﬁrst try] R1 R2 R4 R5 R5 R? R3 Net ”a: ”a ”a: ”at ”is ”(.mzzyﬂ —l —1 +2 +1 —1 F2 +2 WemusinglmuleﬂaiﬂlsndlnﬂaﬁaﬂtomkclmsleNazCOthedasimd product],butmmaisumnsunﬁugmgmmﬁngalutofnﬂmdmrﬁcalsCauldwe Synﬂmizne attestation pathwaywiﬁlnﬂnstmnsumptim Dian}! rswmstu‘isisntlmthsn EmmNaCLandm-nelgmeraﬁunormnsumpdm ofanjraftheatmnmtjs— mamjnirlgcumpmnds? In slim wuaﬂs, can wt: ﬁnd multiplying factors It sud: [In the entry in the Net column equals zero for NI-LCL NH}, NH4UH, {NI-LEGO]. MEI-ICU? and NaHCOg'? Applying Eq. [I .2] m thus: six mmpnuntls gives: NH‘CI: ~21», + x: = s NBS: 2X3 _ X4 = '3' NH‘DH: x4 — 215 = {ﬂﬂdsz X5 ‘ 15 = '3 NH-tHCDH: 2X6 _ X? = Mai-ICU}: X? # 2355 = 0m solutiun ﬂiat satisﬁes all thcsc constraints is X3=Xs=Xs=Xs=l X4 = X? = 2 Let's 56!: what happens if we multiply the stoichiomnh‘ic mﬂisisnts for reactions {R4} and (R?) by 1 {Table L2b): T_ Generation£unsumptiun Analysis (if the Solvav Process [second try? Cumpmmd R1 RE R3 R4 R5 HE R? R3 Net ”at ”£2 "a 141’“ ”is ”is X 11W ”:3 ”mu 2 EXWa CaCOa —I It: I] I} II] {I I] I] II] I] The net reaction of the Solvay process {Example 1.4] is 2NaCl + CaCO; -—> N32C03 + CHIC]2 Q4: ﬁrhw émwﬁw tram“; 9/ 4—A-DPA~ Solution Em let‘s mmpielne a gmmreiion—eensumpﬁen analysis of the tradiu'enal scheme: m WT «:11 ﬂ 1 — 1 CEHEFI + l — l U HCI + l + I HM]3 —1 — 1 Cﬁfl‘ClNﬂz +1 _ 1 {J Han +1 +0.5 +2 +35 CaHEN HUI-ID - 1 _ ._ l KECD! —ﬂ.5 —{]_5 ' CoHsNHCGH-Iﬂﬂz + l —l t} KC! +1 + 1 CD ' +1 + 1 m2 +115 +0.5 Hz — 3 -3 CEHENHCEH-INH’J, + l + I New let's calculate the atom manly. using the smichjemeﬂ'ir: eoeﬁieieuts from the “net" {last} mlumu. We need to consider mug"r the reactame [negative ﬁnishin- meu'ie coefﬁcient} and the desired product (4-ADPA} in the atom \$60an calculaljml. CMMIId P" M. H.- M. W Cl: —1 T1 —?1 FWD; —1 :53 ~53 CﬁHSNHCI-lﬂ — 1 121 — :21 Kym3 —n.5 133 —69 H1 — 3 2 —e CEH5NHC6H4NHZ +E :34 +134 _ﬂ_ t "WIM— _ 21% _ —[(uws}+{—‘11}+(—ea] +1—121)+{—es}+(—e}] All menu = (145 Now let‘s complete a generation—consumption analysis of the new scheme: Compound F“ pa :1 M ﬂ;H_.,I"~l'.:l'1 — l —l C‘rHjl‘lvl'l-I2 — l — l CﬁHENHCﬁthU + I — l '3 H20 + l +l H2 -2 “I CﬁHENHCEHﬁHZ +1 +1 and let’s calculate ﬂee elem eetmnmy of the new scheme: Compound PE M, P1“.- Cﬁmmz — 1 123 — 123 CﬁlgNi-Iz —1 93 -93 Hz —2 2 —4 Cﬁl-ISNHCJI4NI-Ie + 1 134 + 134 1' H _ £15; I —1(—1231+li—4931+H11 = “'34 sum Converting from the traditional to the new process increases the stern economy from 1145 to U34. This is a rmnnlkable achievement, which was reengnized by a Presidential Green Chﬂﬂ'llsﬂ'jf Challenge Award. ...
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Problem set # 1 - Solution - AHHﬁHtﬁ 9YM1'HE519 CH4...

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