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35W wk Mt WW’V MM A semibatch system, with a single component of interest: glucose. 0.2 L/h
100 G glucose/L Reactor
Reactor consumption = Reactor
25 g/h t=0 0<t<6 t_6
mg,sys=GOg  ‘
DOFanal sis: — No. of variables _
ugwcose m Speciﬁed ﬂow System variables 2 (reaction, Speciﬁed 1 (initial glucose)
accumulation) comositions
Speciﬁed
 rformance

_ _ ‘ DOF=33=O. We use an integral material balance, with units in g and h. tf tf tf
"‘3;st ’ "’ng9 g f mgind‘ ' fmgputd’ + f Rgd’
to to to 6 6
"18,3st —60 = f20dt0+ f—zsdt =120—150
0 O mg’sys’f = 30 g glucose To calculate the concentration, we need to do a total mass balance, recalling that 1 mL
broth = 1 g. If t f If
msysj ' msysﬂ = f ’hgindt ‘ f ’hgputd’ + f Rgd‘
t0 t0 t0 6
msys’f600=f200dt=1200 0
msys’f=1800g=1.8L Final concentration = 30 g glucose/ 1.8 L or 16.67 g/L. , ...
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 Winter '08
 ali
 Mass Balance, total mass balance, integral material balance, Mt WW’V MM, tf tf

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