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hw4 - Your name PHYS 1304 Homework assignment 4 Due Problem...

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Unformatted text preview: Your name: PHYS 1304, Homework assignment 4 Due September 29, 2009 Problem 1 (2 points) A deuteron (a nucleus that consists of one proton and one neutron) is accelerated through a 2,7 kV potential difference. How much kinetic energy does it gain? Answer in units of J. AU:/ n. "v Problem 2 (2 points) A uniform electric field of Inngi‘iitndce 250 V f In is directed in the positive x—direction. Sup- pose a 1'2 #C charge moves from the origin to point. A at. the coordinates. {‘20 cm, BU cm). 3/ 2.50 V/in (20 €111,330 cm) A ' ’ 0!” " “'hnt is the absolute- valne of the change in potential from the origin to point. A? Ansmrr in units of V. Problem 3 (2 points) A proton (mass = 1.67 x 10—26 kg, charge = 1.60 X 10—19 C) is moving at a speed of 8.50 x 104 m/s at a point in an empty region of space, where the electric potential is 35.0 volts. No force but the force of the electric field characterized by the electric potential acts on the proton. The particle travels to a point in the evacuated region of space where the electric potential is 47.0 Volts. What is the speed of the particle at that point in space? 1 . :4 A i’\ . ~ .. , x ’ .,i 4. fv . . ‘ L»? Mr gr v’\ i ._ {a h ' f 0 It“ W” St, “a f' T. ' (J (a . 1 m i 2 Wm :mvr 3;“ Mi ":ngf‘ Problem 4 (2 points) Consider a solid conducting; sphere with u radius a and Charge Q1 on it. Thei‘v is a conducting spherical shell ccnuxuitrin to the sphere. The shell has an inner radius 1) (with b > a) and outer radius 6 and :12 net charge Q3 on the) shell. Denote the charge 011 the inner 31.11'fzu'e of the shell by Q3 and that on the outer surface of the shell by Q2; Q19 (1 by Q5 '—Q2 Q-lzl Q1 Find the charge Q35] Start the solution by sketching how the charge is distributed on the shell and the sphere. Then which regions have the constant potential. indicate Both questions can be answered if you recall how the charge and potential behave inside conductors in electrostatic equilibrium. Based on these answers and the equation for the potential ~ M232 N3“: ‘ i V(is<r<c)«»—--~ Q—wl“ ( 21232329 } :5 &,[email protected] 5022,34; «fa-w L<V<C 1? W52 7 .. ,. J i .. 2 2 ~~‘nm r9: VOW-”2:23, {2,42% WM 22 .2222 We fif'i ng'éh JFK?» r + -*—‘-~~«-~~~~»~ of a charged sphere/shell, derive the expressw M __ FLUT'WQJ ' MW ’ "r“ I ' ' 2,229: 1 WM Milan sphue “ w _. . . +02 mm m- m c-f- 2i ‘ I: {fly V>R kaobmfi) . {(GZZcfiréc) i lam l Aqrmoi‘ 2 r E (2!. W2 62;: *HCEM’ #fifit (miner) (Sw‘lnfiz) (31:. Q24 ($22 “3102-: ion for Q2 {am N14“? finau$$ S. 43% = coast ( 62:02.4»(9; =1 ,2 {cup mo (Es-«CD Problem 5 (1 point) The electric potential in a certain region is V = one2 + bx + c, Where a = 12 V/mg, b = —10 V/m, and c = 62 V. Determine the position Where the electric field is zero. Answer in units of m. (fr—O ==> gawk-3270 X” W” rm» 4¥ém ...
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