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# Chapter 5 - 3 3 2 2 1 1 v R R v R R v R R v f f f o-= 3 2 1...

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Chapter 5 Operational Amplifier

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Introduction A typical op amp: a) pin configuration, b) circuit symbol An op amp is an active circuit element designed to perform mathematical operation of addition, subtraction, multiplication, division, differentiation, and integration.
Terminal Voltage and Currents V2 +Vcc -Vcc V1 Vo OPAMP + - OUT A Vo Ro Ri V1 A(V2-V1) V2 Vd=V2-V1 (differencial input) Vo=AVd=A(V2-V1) A: gain (open-loop voltage gain)

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Vo Ro Ri V1 A(V2-V1) V2 Actual op amp: Ri(very large); Ro(very small); A(very large) Idealization: Ri=> ; Ro=>0 ; A=> As Vo is limited, we can get from Vo=A(V2-V1) that: V2=V1 As Ri=> , we can get i 1 =0, i 2 =0 i 1 i 2
Ideal op amp 1) i1=0 , i2=0 ; 2) V1=V2 V2 V1 Vo OPAMP + - OUT Ideal op amp model i1 i2

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Applications Inverting Amplifier i f o v R R v 1 - =
Applications Noninverting amplifier i f o v R R v ) 1 ( 1 + = If Rf=0; R1= , then=>

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The voltage follower V i V o + - + - First stage Second stage Applications
Applications

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Unformatted text preview: ) ( 3 3 2 2 1 1 v R R v R R v R R v f f f o + +-= ) ( 3 2 1 3 2 1 v v v v then R R R R if o f + +-= = = = Difference Amplifier 2 2 3 4 1 a b 1 4 2 2 4 3 2 1 1 2 ) / 1 ( ) / 1 ( v R R v R R R R R R v o-+ + = 1 2 4 3 2 1 1 2 1 2 4 3 2 1 ) ( v v v then R R and R R if v v R R v then R R R R if o o-= = =-= = Note: be careful while using nodal analysis, do not set nodal equation at the output terminal. Example: R6 R5 V2 Vi V3 V1 R7 Vo OPAMP +-OUT R4 R3 R8 Find out Vo P.P.5.10 As a voltage follower, v a = v 1 = 2V where v a is the voltage at the right end of the 20 k Ω resistor. As an inverter, v b = Where v b is the voltage at the right end of the 50k Ω resistor. As a summer v = = [6 - 15] = 9V V 5 . 7 v 10 50 2-=- +-b a v 30 60 v 20 60...
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Chapter 5 - 3 3 2 2 1 1 v R R v R R v R R v f f f o-= 3 2 1...

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