Unformatted text preview: p = 4W 3. Since we are assuming the ideal opamp model, v + = v= 0, i + = i= 0 and the current through the resistor R 1 is i s . So, the potential of node 1 is v 1 =i s R 1 . The current through R 2 is i 1 =i s R 1 R 2 . By KCL we get i = i 1i s =i s R 1 R 2i s =i s ( R 1 R 2 +1). i s i R 1 R L R 2 i 1 1 1...
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This note was uploaded on 04/06/2010 for the course EE 102 taught by Professor Pingli during the Fall '08 term at Shanghai Jiao Tong University.
 Fall '08
 PingLi
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