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Unformatted text preview: v t = 1V and k = 1mA / V 2 . Which region is the transistor operating in? Find R . Put your fnal answers in the box below. 5V 8mA 2kΩ R Solution: The transistor is in saturation, since v ds = 5 ≥ v gsv t = v gs1. Thus i d = k 2 ( v gsv t ) 2 . Substituting, we obtain 8mA = 1mA 2 ( v gs1) 2 , which gives v gs = 5V, and there±ore R = ∞ ....
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This note was uploaded on 04/06/2010 for the course EE 102 taught by Professor Pingli during the Fall '08 term at Shanghai Jiao Tong University.
 Fall '08
 PingLi
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