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Unformatted text preview: MATH 128A, SUMMER 2009: HOMEWORK 5 (1) (This is a slightly modified version of 4.7.8.) Show that the quadrature rule R b a f ( x ) dx n i =0 c i f ( x i ) cannot have degree of precision greater than 2 n + 1, regardless of the choice of c ,...,c n and x ,...,x n . Hint: Suppose the nodes ( x i ) and coefficients ( c i ) are fixed. Construct a polynomial f ( x ) of degree 2( n + 1) such that f ( x i ) = 0 for each i , but f ( x ) > 0 for other values of x . (2) 4.9 : 67a [reworded] The Laguerre polynomials { L ( x ) ,L 1 ( x ) ... } form an orthogonal set on [0 , ) with respect to the inner product h f,g i = Z e x f ( x ) g ( x ) dx (i.e., h L i ,L j i = 0 for i 6 = j ). The polynomial L n ( x ) has n distinct zeros x 1 ,...,x n in [0 , ). Let c n,i = Z e x n Y j =1 j 6 = i x x j x i x j dx. Show that the quadrature formula Z e x f ( x ) dx n X i =1 c n,i f ( x i ) has degree of precision 2 n 1. ( Hint : Follow the steps in the proof of Theorem 4.7.): Follow the steps in the proof of Theorem 4....
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This note was uploaded on 04/06/2010 for the course MATH various taught by Professor Tao/analysis during the Spring '10 term at UCLA.
 Spring '10
 tao/analysis
 Math

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