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Chap 3 Sec 5

# Chap 3 Sec 5 - 3.5 Fundamentals of Solution Stoichiometry...

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Chap 3-5 small.doc Page 1 3.5 Fundamentals of Solution Stoichiometry Molarity ( M ) = moles of solute per volume of solution in liters: M = molarity = moles of solute liters of solution = moles L for instance 6 moles of HCl 2 liters of solution = 3 M HCl (we say a 3 molar solution) 1) Preparing a solution: If you weigh out 5.844 g of NaCl (MW or M = 58.44 g/mole) and dissolved it in 500. mL of water, what is the molarity of the solution? a) g ---> moles 5.844 g x 1mole 58.44 g = 0.1000 moles b) mL ---> L 500. mL x 1 L 1000 mL = 0.500 L You do not have to show me this step now. One can simply move the decimal point 3 places to the left , in going from mL to L. Conversely one can go from L to mL by moving the decimal point 3 places to the right. Just keep in mind there will always be more mL than L because they are the smaller unit! c) M = 0.1000 moles 0.500 L = 0.200 M pronounced molar also symbolized with M or M Note that your calculator only says 0.2. It is your responsibility to put in the 0.200 !

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