Exam1-2008-solutions Number4 x0 is 7.746

Exam1-2008-solutions Number4 x0 is 7.746 - ME3212:...

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Unformatted text preview: ME3212: Mechanisms Exam 1: Fall 2008 S 0 I “1717 MAS Name 1. (20 pts) Calculate the number of degrees of fieedom for each of the following mechanisms. Number the links on each mechanism and indicate the degrees of freedom of each joint with a “(1)” or “(2).,, Page 1 of4 Em |~ 5% W5 I i Z) a) “$2 jam—251 ' ? S 4”? 5 F+¢g 3) IS‘HG SZ§+30 6‘6‘ : 5‘5“ ‘ V65 [Mk Q2 Cam make 4: Calm/MR (7C) QZ COS QZ COS jStq’ f4}, (0399 a» at 5H9? fags/he; :445m94 “HZ “Zq. 612 025 92 2‘: [532521090233 605 #0 ‘2 “3.018 :7 g : 21—134mm — Sam/Z 413‘ {613.425 +30z «Io Cos 7L ’ 2 ac“, 5 Z (36>) (£01.34) 2 _ COS 7 : C?3 WE "32 -_.,~ 702*302 “543’”? :,-> y: 32%" é—T—E 7:: 2332' 2;) [3” 5K (-4352VL94./5)-4/i{, a Z, ~92=94UY we \ “3 - V M __ ’ ~\ ' A o amok _: Smgzgjd-«SK <m5n #3523 6! z s _ Zak (Cm/fl) . a! : {<{O- o<->\ .:z<60- 3;: 35:. 674.17 Crag, Pia-W ‘th smegma“: ., ngnq Q: + as §7né3 :: omgnqéq ' -1 4‘: jihé‘; ‘4z3n9g> {a : 0M +44 Cos 94 +45 COS _¢) § : mm? {55 : a; 5m 94 +515 5h ((93%)) :7... 30 5,450.47) Me‘sm(l3.07~3o) ! i l ! i ' a i azs’hg ‘ a _ 61353116} +W57h(%m0) 5017}; Cos/$31.?» —‘ " M —- 214% . S/VL (95 7‘45) : COS $3 await x 3”; at COS éé -' 0K “ qscas ‘93 :~&m9 3 . 3 05?. 51kg: “’0‘; 5h 6’5 V dz -‘ fiecZQg 3.1.9:?(42 5m éz~qs€m93> — m93(qccoséz—qjcos%o§’) I 1 d9; , 1:. “qzfihea +0‘39’”65 2L3 0’92. g:ch out “M? ' 716?, _ 9 3 _6e0187>(415m91 -9155m93) +Qgt‘an93 60593 035/“ M a; ém 93C0$92 “alélnez H *fa/m Q5 (0?; 52m _ N YQ3+170)‘M3 53V) ‘93 : 9!: @méés <93“) 4/5”» 722/ M M;z/><o:<€.z¢lé/ QSTZ /Qz:8\ ch/‘s’ $59? I . ‘ gf—522ZZYO #4107: 93> +69 ‘ose3—X3bpqfim 65» é 6—3;“ : ’7}? V a? w- I‘Uwg £52m : 93°” Hm; e .WWWSSeIzm/zqé (a) , ' M g3 x *0 2010019 {2(a) Z -—¢W,Z%<6 c¢@§) 3 * 0,0044% m4 val/(1814 r? (we 74} 9M WGLSW' r 5m54 ‘QSC'JQV: @361) 7Laej(l)t bugle (2(3): 0.000045- C’CB) T: *L/‘Kvso 7 1363(3) 3 : @ Ooé 600 <23? Veal JC18) 63:” ': Wm: my! : éqJ€° (4) MT“ ...
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This note was uploaded on 04/06/2010 for the course ME ME3212 taught by Professor Jeremys.daily during the Fall '09 term at Tulsa.

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Exam1-2008-solutions Number4 x0 is 7.746 - ME3212:...

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