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Exam1-2009-solutions

Exam1-2009-solutions - édlw‘iw ME3212 Mechanisms Exam#1...

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Unformatted text preview: édlw‘iw ME3212: Mechanisms Exam #1 Instructor: Dr. Jeremy Daily Fall 2009 Department of Mechanical Engineering The University of Tulsa This exam is open book and open notes. , KM: wouli‘q 1. True or. ' ICS is the study of position with respect to time without regard to the forces that cause motion. [Wk / . ,. . flhflr‘cal ~) 2 “101‘ 2. True [email protected] sph a] pair has 1 degree of freedom. 5 3 '/Tru r False: Two degrees of freedom are needed to describe the meshing of both toothed gears and non—slipping friction gears. 4. A four bar mechanism has the following link lengths: 2 in, 2.5 in, 3 in, and 4.5 in. a) Sketch the mechanism as a crank-rocker. b) Does this mechanism satisfy Grashof’s Law? c) What does it mean to satisfy Grashof’s law? 5. Calculate the mobility of the following mechanism. All circles represent toothed gears and the outer gear is fixed. (L: s d l t 4: 32. '1‘ l __ m : St?!) ~zc;)-1 - (Zr-IO-I :/3 mpg [Valet 7.14:5 1‘3 ffiwfllhléw‘ll‘ )‘D MOI/MISM Flame 2% ififars. 6. Given the four-bar linkage in the following diagram where 62 = 45°, r] : 600 mm, r2 = 140 mm, r3 = 690 mm, r4 = 400 mm, (14 : 200 mm, and 4304C : 45° (constant). a) Write down the loop closure equations. b) Determine the angle, 93. c) Determine the coordinates of point C. ”I“ 2 qus @flocwflwoz—‘Iwz 2c mm (6%) W : 35656" 93 : 4/273 : 3670m~u.;77:- @) deéemmm C): M Cy. 6x t V“. 7‘ 0M 09569;, +4?) a? : ’Qq 5mm, '7LL/§°) 2/72 OQMMM 9‘!) we, need 2. )1: acos W 2%st ; i Z s r}! ZL€IO,GQ)(LMO) fl : fi’l. 7?) a, = my —,3 ~7L : mic-M72427? i. E Wt7mq° g 3 J 'CX: (poo +- mobg<71tw+4fl = S‘llz mm) is : mean 71.0” : m 1 j; C 1416‘) 7. Using the Newton-Rahpson method, determine the position of the slider for the following off- set slider crank mechanism where r2 = 2 inches, r3 = 11 inches, e = 1 inch, and 02 2 120°. Start with an initial guess of d : 10 inches and solve for d within 0.001 inches. ...
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