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PracticeExam2 - ME 3212: Mechanisms Practice Exam #2 Fall...

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Unformatted text preview: ME 3212: Mechanisms Practice Exam #2 Fall 2007 1. For the offset slider crank shown below, (a) Differentiate the velocity equations to get the acceleration equations and put into matrix form. (b) Solve for r and 3 . (c) Setup and differentiate the position equations to get the velocity of point D. (d) Solve for the acceleration magnitude and direction of point D. % A B C D O 2 x y 3 2 2 r e where O 2 A = 28 mm, AC = 30 mm, CB = 70 mm, CD = 40 mm, e = 12 mm, r = 79 mm, 2 = 120 , 3 = 22 , 2 = 2 = 20 rad/sec (constant), 3 = 3 . 02 rad/s (CCW), and r =- 371 . 8 mm/s ( ) . The loop closure equations are as follows: O 2 A cos 2 + AB cos 3 = r O 2 A sin 2- AB sin 3 + e = and the velocity equations are:- O 2 A 2 sin 2- AB 3 sin 3 = r O 2 A 2 cos 2- AB 3 cos 3 = 1 2. Design an offset slider-crank mechanism with a stroke of 250 mm, time ratio R T = 1 . 30 and a transmission angle a = 50...
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This note was uploaded on 04/06/2010 for the course ME ME3212 taught by Professor Jeremys.daily during the Fall '09 term at Tulsa.

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PracticeExam2 - ME 3212: Mechanisms Practice Exam #2 Fall...

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