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Unformatted text preview: 1 Homework 1 Exercise 2. Phase of the tone controls its initial value. With cos( o n/f s + o ) , if o = 0 a click would be heard because of the initial value of 1 whereas with o = 90 there would be a smooth beginning . Exercise 4. Su ciently high sampling rate is required to faithfully represent a time varying signal. If the signal frequency starts becoming comparable to the sampling frequency error starts creeping in the sampled representation. In this example, tone of 9000Hz with sampling rate 8000Hz sounds like a low frequency tone whereas with 44100Hz sampling rate it sounds perfectly ne. Since voice signals have frequency content between 10Hz and 20kHz, a sampling frequency 44100Hz is su ently high to represent voice, although in most cases we could do well with lower sampling rates. Homework 2 Exercise 3. z [ n ] has the same range as y [ n ] Exercise 6. For y [ n ] as de ned output would be z [ n ] = x [ N- n ] (just substitute y [ n ] in the given formula of z [ n ] ). Point to be noted here is that y [ n ] is an impulse, thus output would be...
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This note was uploaded on 04/06/2010 for the course ECE 130b taught by Professor Staff during the Winter '08 term at UCSB.
- Winter '08