Solutions to Extra Problems 4 a

Solutions to Extra Problems 4 a - ACTSC 231 Solutions to...

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Unformatted text preview: ACTSC 231 Solutions to Extra Problem Set 4 a 1. B 7 = 500 a 5 j : 05 +500 (1 : 05) & 5 a 12 j : 06 = 500 1 & (1 : 05) & 5 : 05 +500 (1 : 05) & 5 1 & (1 : 06) & 12 : 06 = 5449 : 2189 I 8 = : 05 OB 7 = : 05 (5449 : 2189) = 272 : 46095 P 8 = 500 & 272 : 46095 = 227 : 539 05 b. B 14 = 500 a 10 j : 06 = 500 1 & (1 : 06) & 10 : 06 = 3680 : 043 5 I 15 = : 6 B 14 = : 06 (3680 : 043 5) = 220 : 802 61 P 15 = 500 & 220 : 802 61 = 279 : 197 39 2. j = i (12) 12 = & 1 + : 05 2 ¡ 2 = 12 & 1 = : 004123915 , n = 20 (12) = 240 a) 100000 = Xa 240 j j = ) X = 100000 a 240 j j = 100000( : 004123915) 1 & 1 : 004123915 & 240 = 657 : 125 b) 100000 = 857 : 125 a n j j + Y v n +1 j a n j j = 100000 857 : 125 = ) 1 & (1+ j ) & n j = 100000 857 : 125 = ) 1 & (1 + j ) & n = 100000 j 857 : 125 = ) (1 + j ) & n = 1 & 100000 j 857 : 125 = ) & n ln (1 + j ) = ln & 1 & 100000 j 857 : 125 ¡ = ) n ln (1 + j ) = & ln ( 1 & 100000 j 857 : 125 ) ln(1+ j ) = & ln ( 1 & 100000( : 004123915) 857 : 125 ) ln(1 : 004123915) = 159...
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This note was uploaded on 04/07/2010 for the course ACTSC 231 taught by Professor Chisholm during the Winter '09 term at Waterloo.

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Solutions to Extra Problems 4 a - ACTSC 231 Solutions to...

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