Unit 3- Notes 2-1 - velocity ( V 2 )would be lower An...

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Keywords Graham’s Law Isotope separation Mean free path Non ideal behaviour
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If two gases are at the same temperature KE of the molecules are the same. Since we know KE = ½ mV 2 we can write ½ m 1 V 1 2 = ½ m 2 V 2 2 Here if the first gas molecule has a lower mass (m 1 ) then the velocity (v 1 ) would be higher and for the second gas molecule if the mass (m 2 ) is higher the
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Unformatted text preview: velocity ( V 2 )would be lower An element that exists as a diatomic gas at STP effused at 0.324 times the rate of effusion of He under the same conditions. Identify the element. molecules a (L 2 atm mol-2 ) b (cm 3 mol-1 ) H 2 0.248 26.6 H 2 O 5.52 30.4 CO 1.47 30.4 O 2 1.38 31.7 N 2 1.37 38.7 van der Waal’s constants...
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This note was uploaded on 04/08/2010 for the course CHM CHM140Y5 taught by Professor Dr.krish during the Spring '09 term at University of Toronto.

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Unit 3- Notes 2-1 - velocity ( V 2 )would be lower An...

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