# hw 7 - x )) 50 x d x = d ) Z x 1 / 6 1 + x 1 / 3 d x = e )...

This preview shows pages 1–2. Sign up to view the full content.

Calculus for the Life Science I MAT1330A , MAT1330B, MAT1330E Assignment 7 Due date: Oct. 28 Instructor (circle one): Jing Li , Catalin Rada , Frithjof Lutscher DGD (circle one): 1 , 2 , 3 , 4 Student Name (printed): Student ID Number: Question 1 We consider the function g ( x ) = e x - 2 - cos( x ). a ) Why is there a solution of g ( x ) = 0 between 0 and 1 ? b ) Use Newton’s method with x 0 = 0 to ﬁnd this root. Stop when the diﬀerence between two consecutive iterations is less than 10 - 4 . The solution is approximatively Question 2 Compute the following integrals. a ) Z x 2 - 1 x 2 + 1 d x = b ) Z e x d x = c ) Z (1 + 3 ln(

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: x )) 50 x d x = d ) Z x 1 / 6 1 + x 1 / 3 d x = e ) Z ( x 2 + 1) sin(3 x ) d x = f ) Z e cos( x ) cos( x ) sin( x ) d x = 2 g ) Z ( x 3 + 2) ln( x ) d x = Question 3 Let p ( t ) be the position (in meters) of an object along a straight line at time t (in minutes). We know that the velocity of the object at time t is given by p ( t ) = t sin( t ). Find the position of the object after 15 minutes if initially the object is at 10 meters from the origin. The position after 10 minutes is...
View Full Document

## This note was uploaded on 04/08/2010 for the course MATH MAT1330 taught by Professor Rad during the Spring '10 term at University of Ottawa.

### Page1 / 2

hw 7 - x )) 50 x d x = d ) Z x 1 / 6 1 + x 1 / 3 d x = e )...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online