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Unformatted text preview: Calculus for the Life Sciences I MAT1330 Test 2 Instructor: Jing Li , Catalin Rada , Frithjof Lutscher Question 1 Show that the equation 4 points x + sin( x ) = e − 2 x has at least one solution in the interval [0 , π ]. State the theorem (hypothesis and conclusion) from class that you are using. Solution: Let f ( x ) = x + sin( x ) − e − 2 x . Since f (0) = − 1 < 0 and f ( π ) = π − e − 2 π = 3 . 139725 . . . > 0, and since f is continuous on the interval [0 , π ], we may use the Intermediate Value Theorem to conclude that there exists c ∈ ]0 , π [ such that f ( c ) = 0. Thus, c + sin ( c ) = e − 2 c . Question 2 Consider the discrete dynamical system 6 points x t +1 = ax t 1 + x t − 2 x t , t = 0 , 1 , 2 , 3 , . . ., where x t is the number between of individual after t periods. Consider only a > 0. a ) [2 points] Find all the equilibrium points of this discrete dynamical system. At least one of them will depend on the parameter a . b ) [1 point] Find the values of a for which the equilibrium points in ( a ) are biologically meaningful. c ) [3 points] Determine the stability of the equilibrium points in function of the possible values of the parameter a determined in ( b ). Solution: The updating function of the system is f ( x ) = ax 1 + x − 2 x . a ) The equilibrium points are the solutions of p = f ( p ) = ap 1 + p − 2 p . p = 0 is a possible solution. If p negationslash = 0, we may divide both sides of the equality by p to get 1 = a 1 + p − 2 ⇒ 3 = a 1 + p ⇒ 3(1 + p ) = a ⇒ 3 p = a − 3 ⇒...
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This note was uploaded on 04/08/2010 for the course MATH MAT1330 taught by Professor Rad during the Spring '10 term at University of Ottawa.
- Spring '10