# Ch. 8 - 8.1 14 1 4 9 15 25 36(9 15 2 = 24 2 = 12 18 41 43...

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8.1 14) 1, 4, 9, 15, 25, 36 (9 + 15) ÷ 2 = 24 ÷ 2 = 12 18) 41, 43, 56, 67, 69, 72 Since all numbers appear only once there is no mode. 20) 9, 8, 10, 9, 9, 10, 8 Mode: 9 24) 238+159+87+163+198 = 845 238 159 87 163 +198 845 845 ÷ 5 = 169 169 5)845 5 34 30 45 45 Mean = 169 miles per day 36) 193, 185, 163, 186, 192, 135, 158, 174, 188, 172, 168, 183, 195, 165, 183 a) 193+185+163+186+192+135+158+174+188+172+168+183+195+165+183=2640 193 185 163 186 192 135

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174 188 172 168 183 195 165 +183 2640 2640 ÷ 15 = 176 176 15)2640 15 114 105 90 90 b) 135, 158, 163, 165, 168, 172, 174, 183, 183, 185, 186, 188, 192, 193, 195 Median: 183 c) In this case the median number is the most useful representative of the final examination. I justify it that both median and mode coincide, so they have priority over the mean. Another explanation could be adding the set of three numbers in the middle: 174 + 183 + 183 = 540/3 = 180. From this we see that the number 180 is closer to 183 than 176 is to 183. So, this should prove that the median is more useful. 8.2
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Ch. 8 - 8.1 14 1 4 9 15 25 36(9 15 2 = 24 2 = 12 18 41 43...

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