14-1p584 - 14-1p584.wpd Page 1 of 3 Summary P584#1-5...

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14-1p584.wpd Page 1 of 3 Summary: P584 #1-5; P587 #1-6 P584 1) 22 a) It shows complete combustion, only products are CO and H O. b) 2) 5 1 a) C H + 8O 5CO + 6H O 8 1 82 b) 2C H + 25O 16CO + 18H O 26 2 2 2 c) 2C H + 5O CO + 2CO + C + 6H O 2 2 2 3C H + 7O 2CO + CO + 3C + 9H O (there are an infinite number of other possibilities) 3) a) There are an infinite number of possibilities, here is one: 41 0 2 2 2 C H + 4O CO + CO + 2C + 5H O 4 1 02 b) 2C H + 13O 8CO + 10H O 25 52 2 2 2 4) C H + 38O 25CO + 26H O 5) a) b) There are an infinite number of possibilities, here are two: 13 28 2 2 2 C H + 15O 5CO + 6CO + 2C + 14H O 13 28 2 2 2 C H + 11O 4CO + 2CO + 7C + 14H O c) This is incomplete combustion, as CO and C are produced in addition to CO and H O P587 1) Complete combustion of a hydrocarbon uses the most oxygen to hydrocarbon ratio, and produces only carbon dioxide and water. Incomplete combustion uses a lower oxygen to
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14-1p584.wpd Page 2 of 3 hydrocarbon ratio, and produces carbon dioxide, water, carbon monoxide and carbon. A
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This note was uploaded on 04/09/2010 for the course SCIENCE CHEM taught by Professor M during the Spring '09 term at McMaster University.

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14-1p584 - 14-1p584.wpd Page 1 of 3 Summary P584#1-5...

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