14-4p607 - 14-4p607.wpd Page 1 of 1 Summary: P607 #18-21;...

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14-4p607.wpd Page 1 of 1 Summary: P607 #18-21; P611 #22-24 P607 18) Q = mC Ä T Q = 500.0 g X 4.184 J/g C X -1.10 C 00 Q = -2.30 kJ 19) Q = mC Ä T Q = 1.00 kg X 4.184 kJ/kg C X 3.00 C Q = 12.6 kJ 20) a) Q = mC Ä T Q = 100 g X 4.184 J/g C X (29.6 C - 21.7 C) 0 Q = 3.31 kJ 21) a) Q(water) = 1.00 kg X 4.184 kJ/kg C X (25.2 C - 20.0 C) = 21.8 kJ 0 Q(substance) = -21.8 kJ b) C = Q ÷ m Ä T C = -21.8 kJ ÷ (0.0920 kg X (25.2 C - 55.0 C) = 7.95 kJ/kg C
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This note was uploaded on 04/09/2010 for the course SCIENCE CHEM taught by Professor M during the Spring '09 term at McMaster University.

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