# fa06hw11soln - answer to that integral is f(t which is in...

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Fall 2006 HW#11 Solutions Ch9: # 9-12, 15, 17; Ch10: # 2, 4, 10, 12

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Ch. 9 #17 Suppose that t is measured in seconds, f(t) is measured in volts and δ(t -t 0 ) is dimensionless. Then the integral of f(t) δ(t -t 0 ) over t would give dimension V*sec since it’s summing the area. But we know the

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Unformatted text preview: answer to that integral is f(t ), which is in Volts. Hence, δ(t-t ) has to have unit 1/sec. In general, its unit is the inverse of that of the variable of integration (i.e. its parameter): 1/sec, 1/m, C/m...
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## This note was uploaded on 04/09/2010 for the course ECE 210 taught by Professor Staff during the Spring '08 term at University of Illinois, Urbana Champaign.

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fa06hw11soln - answer to that integral is f(t which is in...

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