Eng 106
Homework #2 Solution
Winter 2010
2.40
Given: Cash deposits and withdrawals (negative amounts) below, i=12%/yr.
EOY:
0
1
2
3
4
5
6
7
8
9
10
Flow:
1,000
800
600
400
200
0
C
2C
3C
4C
5C
Find: the one of four values of C given in the book that makes the deposit series equivalent to the withdrawal series.
Use linear gradient relationships for both the deposits and withdrawals.
There are several correct ways of addressing this problem, but all will give the same result. Here is one possibility:
bring all amounts to EOY 4.
1000(F/A, 12%, 5) – 200(P/G, 12%, 5)(F/P, 12%, 5) – C(P/G, 12%, 6) = 0
Using table values: 1000*6.3528 – 200*6.3970*1.7623 – C*8.9302 = 0
Solve for C = 458.90, which is answer (d) given in the book
2.43
What is the amount A of each of 10 equal annual deposits, the first being @EOY 1, that can provide five
annual withdrawals, where the first withdrawal of $3,000 is made @EOY 11 and subsequent withdrawals
increase at the rate of 6% per year over the previous year’s, if
a) i=8%/yr
There are multiple ways of solving this. One is to bring the two series to EOY 10.
A(F/A, 8%, 10) – $3k(P/A
1
, g, i, N) = 0
where g=6%, i=8%, N=5
A*14.4866  $3k{[1(1.06)
5
(1.08)
5
]/(0.080.06)} = 0
A*14.4866  $13,383.92 = 0
Solve for A = $923.88
b) i=6%/yr
Bringing the two series to EOY 10:
A(F/A, 6%, 10) – $3k(P/A
1
, g, i, N) = 0
where g=i=6%, N=5
A*13.1808  $3k{5/1.06} = 0
A*13.1808  $14,150.94 = 0
Solve for A = $1,073.60
2.53
Given: Deposits and interest rates shown below, current balance = $1,000.
Year:
4
3
2
1
0
Deposit @EOY, $:
200
X
0
300
0
i during the year, %/yr
6
8
12
15
Find: Amount X of deposit @EOY 3. there are many possible approaches, although the easiest is to apply the
This preview has intentionally blurred sections. Sign up to view the full version.
View Full Document
This is the end of the preview.
Sign up
to
access the rest of the document.
 Winter '10
 Hartsrough
 annual interest rate, /Yr

Click to edit the document details