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Unformatted text preview: 4? 10T/F Pr [T] =0.6 Pr [exactly 8T] =? n=10 Pr [exactly 8T] = C(10,8)∙ ( . ) ( . ) 0 6 8∙ 0 4 2 k=8 =45∙(0.16)∙ ( . ) 0 6 8 p=0.6 = (7.2)∙ ( . ) 0 6 8 1p=0.4 = 0.120932 5.A skeeball champion gets a 50point roll 80% of the time. What is the probability that he will make at least 4 50point rolls out of 5 attempts? Answer 0.4096 CORRECT CORRECT Your answer is only for 4 successes, but the question asks you AT LEAST 4? Pr[Success]= 0.8 n=5 k= at least 4 → k=4 and k=5 p=0.8 1p=0.2 Pr[at least 4 Successes]= Pr[4S]+Pr[5S] =C(5,4)∙ . . + , . . = 0 84∙0 21 C5 5∙0 85∙0 20 =5∙(0.2) ∙ . 0 84 + . 0 85 = = . 0 84 + . 0 85 = 0.4096+ 0.32768 = =0.73728...
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This note was uploaded on 04/10/2010 for the course BUS M 118 taught by Professor Chrisdona during the Spring '09 term at IUPUI.
 Spring '09
 CHRISDONA

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