assn4sol - Chemistry 350 Assignment 4 Solutions November...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Chemistry 350 Assignment 4 Solutions November 24, 2004 1. The gas-phase decomposition of acetic acid at 1189 K proceeds by way of two parallel reac- tions: CH 3 COOH CH 4 + CO 2 k 1 = 3 . 74 s - 1 CH 3 COOH H 2 C = C = O + H 2 O k 2 = 4 . 65 s - 1 What is the maximum percentage yield of the ketene CH 2 CO obtainable at this temperature? Answer: Since [ CH 2 CO ] = k 1 k 1 + k 2 × [ CH 3 COOH ] 0 then [ CH 2 CO ] [ CH 3 COOH ] 0 = k 1 k 1 + k 2 × 100% = 4 . 65 s - 1 3 . 74 s - 1 + 4 . 65 s - 1 × 100% = 55 . 4% 2. The second-order rate constants for the reaction of oxygen atoms with aromatic hydrocarbons have been measured (Atkinson and Pitts, J. Phys. Chem. 79, 295 (1975)). In the reaction with benzene, the rate constants are 1.44 × 10 7 L mol - 1 s - 1 at 300.3 K, 3.03 × 10 7 L mol - 1 s - 1 at 341.2 K, and 6.9 × 10 7 L mol - 1 s - 1 at 392.2 K. Find the Arrhenius activation energy and pre-exponential factor (Arrhenius plot), as well as the enthalpy and entropy of activation (Eyring plot). Answer: Temp 1/T k ln(k) k/t ln(k/t) 300.3 0.003330003 1.44E+07 1.65E+01 4.80E+04 10.77795679 341.2 0.002930832 3.03E+07 1.72E+01 8.88E+04 11.39418945
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 04/11/2010 for the course CHEM 1101 taught by Professor Leroy during the Spring '10 term at University of Toronto- Toronto.

Page1 / 7

assn4sol - Chemistry 350 Assignment 4 Solutions November...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online