W6.ans - -2 CHEMISTRY 114 Spring 2010 Dr Audrey Dell...

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Unformatted text preview: -2- CHEMISTRY 114 - Spring 2010 Dr. Audrey Dell Hammerich Worksheet - Week 6 1. Hydrogen peroxide can act as an oxidizing or reducing agent as in the unbalanced reaction H O O .. - “2 ‘2‘(aq) —> 02(g) ant/Wen . “flaky a; a) Balance the reaction in acidic solution by the half-reaction method. on L3 ) + a “ 0‘“) 0x3 “10‘ -) 0,9419; ZED: H10“. 121;: .4, “up 3* " 3"" an" M “gotta? 4' 91(5) + 13*LL6) file,” “1031“)... amiss) +- 16 ~41 lflgote). b Write the anod half-reaction. ) . e “3921‘sl 62 9,35) t- amces) eu- c) What is the product of H202 reduction? “9.0 (L3 d) For the reaction, AH°I= —189.32 kJ moi“l and AS° = 57.1 J inor1 K—I. What is the equilibrium constant for the reaction at 25°C? AG:- AG" 4' (arm; 5&‘7 A630, 5&1 [1. 41 X 1036] _-, K. evbb'lm' ., e” “H" -‘r MN )lu: % 0‘, g: L-lfl31Xtooa) - ms. 15'( 510‘ F 9. sweet 9.49.15) ' e) Will an electrochemical cell based on this reaction be voltaic (galvanic) or electrolytic? Explain in one sen— tence, w’LLmuu Eat? Vomit» Pow smoom unbmws MD takstmw WM. momma-mus &41.uwto“- Ewmab‘mo Fort a: um to“! 2. Electrolysis of a molten metal chloride, MC13, with a current of 6.50 A for 1397 s deposits 1.41 g of the metal at the cathode. What is the metal M? Mal" {w 3:: “7 M :7 n‘. '3» 33‘ mass 1% [Sc] (91* let myd‘ - ., zxmssxi 3CLMOLQL (435) H Mn 32!: 4.5mm“) 1 H53 glmc 3. Consider the following half—reactions measured at pH 0: .4 new ° — — o ‘ *5. are. Brzl) + 2‘3: ~—> 213i(aq) E =1.065V 6:4,. 0%: Br0§(aq) + 6 H+(aq) + 5 e‘ —> 1/2Br2(l) + 3 H20(l) E° = 1.52 V a) What are the products of bromine disproportionation? Br’) (5'03. C6 WW eminence Ox PHD RED) b) Will bromine disproportionate spontaneously at pH 0? Why or why not? [N o] I F." (on MR 1.005 - 1.5%: ~ .. 0.455 4 0 =1, our 51300114015005 0) Which is the stronger reducing agent at pH 0: Br2(l) or Br"(aq)? Why? [Br‘] I 57109qu (wbouuo er WM A Gmmn Twowcx To at! 01(91)th OIL-A Lease» fennwm To 53 moves» ‘ 5r ,5.” cat-- on 99:11“) 6 3..- 4, m1.) Is 4.9M lOMkE er; axioms» (err-7 éf'oa‘) Is - (.59. (LE-‘66 “swowrhwtsvus'o 4. A voltaic cell is constructed in which the overall reaction is L00“. 1? P E’( Pb . > :5.) M?€ND N D g ~b.m Swazi 0V Pb(s) + 2H+(aq) —> Pb2+(aq) + H2(g) , v a)-~ Calculate E” for this cell at 25°C. 59-. 0- (-0.6) - 0.13 [0.13 V] b) Chloride ions are added until PbC12(s) precipitates in the anode compartment and [Cl‘] reaches 0.15 M. At that point, the cell voltage is 0.22 V. the pH is O, and PH2 = 1.0 atm. Calculate [Pb2+] under these conditions. 3w} 3'2“,“ W In Q 'TM‘l’} UH} ‘7 34*]: lO'P-Ha- 100:! 1+ no -1 mam-en‘s) 0. lb : an, .. 005'le £03, [1719 ‘2} 2 [Phat]: l0 ( I 051 9-. . . c) Estimate the solubility—product constant KSlD of PbClz. 3" “A XLO‘Q [2.0 X 10—5] 1C5? 9o.- P130416) '2 Pb” e 2.0:: ...
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