Solution2

Solution2 - PHYS 434: Assignment 2 solutions Problems 3.37...

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PHYS 434: Assignment 2 solutions Problems 3.37 The fish has apparent depth a and physical depth d , as illustrated above. Begin with Snell’s Law: sin θ i = n w sin t Referring to the figure: x = r sin i = R sin t Thus r R = sin t sin i = 1 n w Since a = r cos i , d = R cos t We obtain a d = r R cos i cos t = 1 n w cos i sin 2 t = 1 n w cos i 1 1 n w 2 sin 2 i = cos i n w 2 sin 2 i . Problem 3.40 See the code in Problems 3.13 and 3.27. Modify the index values to plot r perp , r par , t perp , and t par vs. i for internal and external incidence; and the R and T counterparts vs. i for internal and external incidence.
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Problem 3.41 A cell with Brewster windows that you design using window material with refractive index 2.42 should look like the following: The Brewster angle for external incidence is θ B = tan 1 n t n i = tan 1 2.42 = 67.5 The angles should be labeled carefully. Problem 3.47 (a) Begin with Equation 3.90: n r 1 + Ne 2 2 m ε 0 f j ω j 2 2 ( ) j 2 2 ( ) 2 + γ j 2 2 j Let j = 1 , and express as an equality: n r = 1 + Ne 2 2 m 0 f 1 1 2
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Solution2 - PHYS 434: Assignment 2 solutions Problems 3.37...

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