Spring 2010 - HW02_Solution

# Spring 2010- - banuelos(ojb93 – Homework 02 – florin –(58140 1 This print-out should have 11 questions Multiple-choice questions may continue

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Unformatted text preview: banuelos (ojb93) – Homework 02 – florin – (58140) 1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points The position-versus-time graph below de- scribes the motion of three different bodies (labeled 1, 2, 3). 1 2 3 x B x A t A t B x t A B Consider the average velocities of the three bodies. Which of the following statements is correct? 1. ¯ v 1 = ¯ v 2 = ¯ v 3 correct 2. ¯ v 1 > ¯ v 2 and ¯ v 3 > ¯ v 2 3. ¯ v 1 > ¯ v 2 > ¯ v 3 4. ¯ v 1 < ¯ v 2 < ¯ v 3 Explanation: Average velocity is ¯ v = displacement time = x B- x A t B- t A . All three bodies have exactly same displace- ment in exactly same time, so the average velocities are exactly equal: ¯ v 1 = ¯ v 2 = ¯ v 3 . 002 (part 1 of 3) 10.0 points The position of a car coasting down a hill was observed at various times and the results are summarized in the table below. time distance 0 s . 93 m 1 s 1 . 8 m 2 s 11 . 1 m 3 s 26 . 3 m 4 s 43 . 4 m 5 s 62 m Find the average velocity of the car during the first second....
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## This note was uploaded on 04/11/2010 for the course PHYSICS 58100 taught by Professor Florin during the Spring '10 term at University of Texas at Austin.

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Spring 2010- - banuelos(ojb93 – Homework 02 – florin –(58140 1 This print-out should have 11 questions Multiple-choice questions may continue

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